If a charged pion that decay in 10−8 second in its own rest frame is to travel 30 meters in the laboratory before decaying, the pion’s speed must be most nearly
A. 0.43 × 108 m/s
B. 2.84 × 108 m/s
C. 2.90 × 108 m/s
D. 2.98 × 108 m/s
E. 3.00 × 108 m/s
(GR0177 #33)
Solution:
v = v0/γ
with γ = 1/(1 − v2/c2)½
Given:
t0 = 10−8 second
L0 = 30 meters
v0 = L0/t0 = 30 × 108 = 10(3 × 108) = 10c
v = v0(1 − v2/c2)½
v2 = v02(1 − v2/c2) = (v02 − v2v02/c2) = 100c2 − 100v2
101v2 = 100c2
v = (100/101)c = 0.99c = 0.99(3 × 108) ≈ 2.98 × 108 m/s
Answer: D
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