In a non relativistic, one-dimensional collision, a particle of mass 2m collides with a particle of mass m at rest. If the particles stick together after the collision, what fraction of the initial kinetic energy is lost in the collision?
B. 1/4
C. 1/3
D. 1/2
E. 2/3
(GR0177 #04)
Solution:Conservation of Momentum (inelastic collision):
mava + mbvb = (ma + mb)v'
2mva + m · 0 = (2m + m)v'
2va = 3v' → v' = 2va / 3
KEi − KEf = ( ½ mava2 + ½ mbvb2 ) − ½ ( ma + mb ) (v' )2
= mva2 − ½ ( 2m + m ) (2va / 3)2
= mva2 − ⅔ mva2
= ⅓ mva2
Answer: C
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