In a double-slit interference experiment, d is the distance between the centers of the slits and w is the width of each slit, as shown in the figure above. For incident plane waves, an interference maximum on a distant screen will be “missing” when
A. d = √2 w
B. d = √3 w
C. 2d = w
D. 2d = 3w
E. 3d = 2w
(GR9277 #20)
Solution:
For double-slit interference, d is always bigger than w
→ (C) and (E) are FALSE
Constructive or destructive patterns of interference (single or double slits) only deals with integer and half integer factors.
→ (A) and (B) are FALSE
Answer: D
Calculation:
“missing” = destructive pattern (minimum intensity).
For double slit: d sin θ = (m + 1/2) λ; m = 0, 1, 2, 3, ...
For single slit: w sin θ = mλ; m = 1, 2, 3, ...
d/w = (m + 1/2)/m
Take m = 1,
d/w = 3/2
2d = 3w
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