Optics - Interference



In a double-slit interference experiment, d is the distance between the centers of the slits and w is the width of each slit, as shown in the figure above. For incident plane waves, an interference maximum on a distant screen will be “missing” when

A. d = √2 w
B. d = √3 w
C. 2d = w
D. 2d = 3w
E. 3d = 2w
(GR9277 #20)
Solution:

For double-slit interference, d is always bigger than w
→ (C) and (E) are FALSE

Constructive or destructive patterns of interference (single or double slits) only deals with integer and half integer factors.
→ (A) and (B) are FALSE

Answer: D


Calculation:

“missing” = destructive pattern (minimum intensity).
For double slit: d sin θ = (m1/2) λm = 0, 1, 2, 3, ...
For single slit: w sin θ mλ; = 1, 2, 3, ...

d/w =  (m + 1/2)/m
Take m = 1,
d/w = 3/2
2d = 3w

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