The binding energy of a heavy nucleus is about 7 million electron volts per nucleon, whereas the binding energy of a medium-weight nucleus is about 8 million electron volts per nucleon. Therefore, the total kinetic energy liberated when a heavy nucleus undergoes symmetric fission is most nearly
A. 1876 MeV
B. 938 MeV
C. 200 MeV
D. 8 MeV
E. 7 MeV
(GR9677 #64)
Solution:
KE = Ef − Ei
Symmetric fission: the splitting of the nucleus into two fragments of approximately equal mass.
AX → A1Y + A2Z
with A1 = A2 = A/2 and Y = Z (for symmetric fission)
A Ei → A1 Ef 1 + A2 Ef 2 = 2(A/2) Ef = A Ef
KE = A Ef − A Ei = A (8 − 7) MeV/nucleon = A MeV/nucleon
For heavy nucleus, A ≈ 200 nucleons. Example: 238U → A ≈ 238 nucleons
→ KE ≈ 200 MeV
Answer: C
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