The angular separation of the two components of a double star is 8 microradians, and the light from the double star has a wavelength of 5500 angstroms. The smallest diameter of a telescope mirror that will resolve the double star is most nearly
B. 1 cm
C. 10 cm
D. 1 m
E. 100 m
(GR9277 #68)
Solution:
Rayleigh telescope resolution limit: sin θ = 1.22 λ/D
D = 1.22 λ/sin θ = 1.22 (5500 × 10−10 m) / sin (8×10−6)
Since θ ≪, assume sin θ ~ θ
D = (1.22 × 5.5 / 8) × 103 × 10−10 × 106 ≈ 10−1 m = 10 cm
Answer: C
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