The ground state of the helium atom is a spin
A. singlet
B. doublet
C. triplet
D. quartet
E. quintuplet
Spectroscopic notation: N2s+1 Lj
2s + 1 = multiplicity
Singlet: 2s + 1 = 1, s = 0
Doublet: 2s + 1 = 2, s = 1/2
Triplet: 2s + 1 = 3, s = 1
Electron configuration of Helium: 1s²
Pauli Exclusion Principle: no two electrons can have exactly the same quantum number.
ms1 = ½ and ms2 = −½
Total spin quantum number, s = ½ + (−½) = 0
Multiplicity, 2 · 0 + 1 = 1 → Singlet
Answer: A
A. singlet
B. doublet
C. triplet
D. quartet
E. quintuplet
(GR9277 #59)
Solution:
Spectroscopic notation: N2s+1 Lj
2s + 1 = multiplicity
Singlet: 2s + 1 = 1, s = 0
Doublet: 2s + 1 = 2, s = 1/2
Triplet: 2s + 1 = 3, s = 1
Electron configuration of Helium: 1s²
Pauli Exclusion Principle: no two electrons can have exactly the same quantum number.
ms1 = ½ and ms2 = −½
Total spin quantum number, s = ½ + (−½) = 0
Multiplicity, 2 · 0 + 1 = 1 → Singlet
Answer: A
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