The ground state configuration of a neutral sodium atom (Z = 11) is
A. 1s2 2s2 2p5 3s2
B. 1s2 2s3 2p6
C. 1s2 2s2 2p6 3s
D. 1s2 2s2 2p6 3p
E. 1s2 2s2 2p5
Z = 11 → 1s2 2s2 2p6 3s1
Answer: C
Note:
Electron configuration:
A. 1s2 2s2 2p5 3s2
B. 1s2 2s3 2p6
C. 1s2 2s2 2p6 3s
D. 1s2 2s2 2p6 3p
E. 1s2 2s2 2p5
(GR9277 #58)
Solution:Z = 11 → 1s2 2s2 2p6 3s1
Answer: C
Note:
Electron configuration:
l = 0 | l = 1 | l = 2 | l = 3 | # of electrons | |
---|---|---|---|---|---|
n = 1 | 1s2 | 2 | |||
n = 2 | 2s2 | 2p6 | 8 | ||
n = 3 | 3s2 | 3p6 | 3d10 | 18 | |
n = 4 | 4s2 | 4p6 | 4d10 | 4f14 | 32 |
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