In the circuit shown above, the resistances are given in ohms and the battery is assumed ideal with emf equal to 3.0 volts The resistor that dissipated the most power is
A. R1
B. R2
C. R3
D. R4
E. R5
(GR9277 #32)
Solution:
Power, P = VI = I2R → P ∝ R
R3 and R4 are in parallel → R34
R34 and R5 are in series → R345
R2 and R345 are in parallel → R2345
R1 is the highest resistance → dissipated the most power.
Answer: A
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