For an ideal gas, the specific heat at constant pressure Cp is greater than the specific heat at constant volume Cv because the
- Gas does work on its environment when its pressure remains constant while its temperature is increased.
- Heat input per degree increase in temperature is the same in processes for which either the pressure or the volume is kept constant.
- Pressure of the gas remains constant when its temperature remains constant.
- Increase in the gas’s internal energy is greater when the pressure remains constant than when the volume remains constant
- Heat needed is greater when the volume remains constant than when the pressure remains constant.
(GR8677 #14)
Solution:
(A) TRUE.
Heat Capacity: C = Q/dT
First law of Thermodynamics: the change in internal energy of a system dU is equal to the heat Q added and the work, W done on or by the system
→ dU = Q ± W
W done on the system → +W
W done by the system → −W
Gas (the system) does work on its environment
W done by the system
dU = Q − W
At constant V:
Work, W = PdV = 0
Q = dU
Cv = dU/dT
At constant P:
Work, W = PdV ≠ 0
Q = dU + W
Cp = dU/dT + PdV/dT = Cv + PdV/dT
Cp Cv
(B) FALSE.
This means Cp = Cv, but according to A, Cp Cv
(C) FALSE.
Ideal gas law: PV = NkT
If T constant, P changes if V changes.
(D) FALSE.
Heat Capacity, C = Q/dT does not depend on the gas’ internal energy, U
(E) FALSE.
See A. At constant V, Q = dU.
At constant P, Q = dU + W.
Answer: A
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