Sodium has eleven electrons and the sequence in which energy levels fill in atom is 1s, 2s, 2p, 3s, 3p, 4s, 3d, etc. What is the ground state of sodium in the usual notation 2s+1Lj?
A. 1S0
B. 2S1/2
C. 1P0
D. 2P1/2
E. 3P1/2
(GR8677 #84)
Solution:
11 electrons → 1s2, 2s2, 2p6, 3s1
3s1 → 1 electron with spin ½ → s = 1/2 → multiplicity = 2s + 1 = 2(1/2) + 1 = 2
3s1 → Subshell s → l = 0 → j = l + s = 0 + 1/2 = 1/2
3s1 → Subshell s → L = S
Spectroscopic Notation: 2s+1Lj → 2S1/2
Answer: B
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