The battery in the diagram above is to be charged by the generator G. The generator has a terminal voltage of 120 volts when the charging current is 10 Amperes. The battery has an emf of 100 volts and an internal resistance of 1 Ohm. In order to charging current, the resistance R should be set at
A. 0.1 Ω
B. 0.5 Ω
C. 1.0 Ω
D. 5.0 Ω
E. 10.0 Ω
(GR8677 # 24)
Solution:
Potential difference across the resistor R:
V = IRt = VGenerator − VBattery = 120 − 100 = 20 V
Total resistance:
Rt = R + Rinternal = R + 1
V = IRt = I(R + 1) = 10(R + 1) = 20 VR = 1 Ω
Answer: C
No comments :
Post a Comment