Showing posts with label Velocity. Show all posts
Showing posts with label Velocity. Show all posts

Sound and Wave - Wave Phenomena


Consider a particle moving without friction on a rippled surface, as shown above. Gravity acts down in the negative h direction. The elevation h(x) of the surface is given by h(x) = d cos (kx). If the particle starts at x = 0 with a speed v in the x direction, for what values of v will the particle stay on the surface at all times?

A.
B.
C.
D.
E. 
(GR9677 #83)
Solution:

Gravity pulls the particle down. 
Particle will stay on the surface if  amax g

For a wave, amax = ω2A = ω2d
(d = amplitude)

Velocity of the particle: v =  λ 

From the picture: λ = 2π/k

v = 2π/kT  = ω/k
v2 = ω2/k2
ωv2k2

amax v2k2
v2 = g/k2d
v = √(g/k2d)

Answer: D 

Thermal Physics - Conduction Electron

The Fermi temperature of Cu is about 80,000 K. Which of the following is most nearly equal to the average speed of a conduction electron in Cu? 

A. 2 × 10−2 m/s
B. 2 m/s
C. 2 × 102 m/s
D. 2 × 104 m/s
E. 2 × 106 m/s
(GR9277 #23)
Solution:

TF = 8 × 104 K
me = 9.11 × 10−31 kg
k = 1.38 × 10−23 J/K

Fermi energy = Kinetic energy



Answer: E

Classical Mechanics - Wave equation

The equation where A, T, and λ are positive constants, represents a wave whose

A. Amplitude is 2A
B. Velocity is in the negative x–direction
C. Period is T/λ
D. Speed is x/t
E. Speed is λ/T
(GR8677 #04)
Solution:

(A) FALSE.
Amplitude  = maximum displacement = ymax = A.

(B) FALSE.
For a wave traveling to the right (positive x-direction): y = ƒ(xvt)
(x − vt) = constant.
As t increases, x must increases to keep (x − vt) = constant

For a wave traveling to the left (negative x-direction): y = ƒ(x + vt)
As t increases, x decreases to keep (x + vt) = constant.

The problem gives:  y = ƒ(vtx)
As t increases, x must increases to keep (x − vt) = constant.
The waves is traveling to the right.

(C) FALSE.
The unit of T/λ (second/meter) does not match with the unit is period (second).

(D) FALSE.
The speed of  the wave is λ/T.

(E) TRUE.
See D.

Answer: E