Given that the binding energy of the hydrogen atom ground state is E0 = 13.6 eV, the binding energy of n = 2 state of positronium (positron-electron system) is
A. 8E0
B. 4E0
C. E0
D. E0/4
E. E0/8
Energy levels of Positronium is half those of Hydrogen (See GR8677 #99)
En(H) = − 13.6 / n²
En(Ps) = ½ En(H)
For n = 2,
E2(Ps) = ½ × ( − 13.6 / 2²) = − E0/8
Answer: E
A. 8E0
B. 4E0
C. E0
D. E0/4
E. E0/8
(GR9277 #30)
Solution:
Energy levels of Positronium is half those of Hydrogen (See GR8677 #99)
En(H) = − 13.6 / n²
En(Ps) = ½ En(H)
For n = 2,
E2(Ps) = ½ × ( − 13.6 / 2²) = − E0/8
Answer: E
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