Quantum Mechanics - Spectroscopic Notation

A 3p electron is found in the 3P3/2 energy level of a hydrogen atom. Which of the following is true about the electron in this state?

A. It is allowed to make an electric dipole transition to the 2S1/2 level
B. It is allowed to make an electric dipole transition to the 2P1/2 level
C. It has quantum numbers l = 3, j = 3/2, s = 1/2
D. It has quantum numbers n = 3, j = ls = 3/2
E. It has exactly the same energy as it would in the 3D3/2 level
(GR9677 #41)
Solution:

Spectroscopic notation: N2s+1 Lj=l+s

For 3P3/2  

P → l = 1
j = 3/2

→ (C) and (D) are FALSE

Selection rules (for electron transition):
1.    Principal quantum number      :     n = anything
2.Orbital angular momentum:l = ±1
3.Magnetic quantum number:ml = 0, ±1
4.Spin:s = 0
5.Total angular momentum:j = 0, ±1, but j = 0 ↛j = 0


(A) TRUE
Transition for ∆l = 0 is allowed.

(B) FALSE
Transition for ∆l = 0 is not allowed.

(E) FALSE
Electron can not move to different energy level (P to D) while maintaining the same energy.

Answer: A

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