A 3p electron is found in the 3P3/2 energy level of a hydrogen atom. Which of the following is true about the electron in this state?
A. It is allowed to make an electric dipole transition to the 2S1/2 level
B. It is allowed to make an electric dipole transition to the 2P1/2 level
C. It has quantum numbers l = 3, j = 3/2, s = 1/2
D. It has quantum numbers n = 3, j = l, s = 3/2
E. It has exactly the same energy as it would in the 3D3/2 level
Solution:
Spectroscopic notation: N2s+1 Lj=l+s
P → l = 1
j = 3/2
→ (C) and (D) are FALSE
(A) TRUE
Transition for ∆l = 0 is allowed.
(B) FALSE
Transition for ∆l = 0 is not allowed.
(E) FALSE
Electron can not move to different energy level (P to D) while maintaining the same energy.
Answer: A
A. It is allowed to make an electric dipole transition to the 2S1/2 level
B. It is allowed to make an electric dipole transition to the 2P1/2 level
C. It has quantum numbers l = 3, j = 3/2, s = 1/2
D. It has quantum numbers n = 3, j = l, s = 3/2
E. It has exactly the same energy as it would in the 3D3/2 level
(GR9677 #41)
Spectroscopic notation: N2s+1 Lj=l+s
For 3P3/2 :
j = 3/2
→ (C) and (D) are FALSE
Selection rules (for electron transition):
1. | Principal quantum number | : | ∆n = anything |
2. | Orbital angular momentum | : | ∆l = ±1 |
3. | Magnetic quantum number | : | ∆ml = 0, ±1 |
4. | Spin | : | ∆s = 0 |
5. | Total angular momentum | : | ∆j = 0, ±1, but j = 0 ↛j = 0 |
(A) TRUE
Transition for ∆l = 0 is allowed.
(B) FALSE
Transition for ∆l = 0 is not allowed.
(E) FALSE
Electron can not move to different energy level (P to D) while maintaining the same energy.
Answer: A
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