A beam of electrons is accelerated through a potential difference of 25 kV in an X-ray tube. The continuous X-ray spectrum emitted by the target of the tube will have a short wavelength limit of most nearly
A. 0.1 Å
B. 0.5 Å
C. 2 Å
D. 25 Å
E. 50 Å
(GR9277 #80)
Solution:
Energy: E = pc
Wavelength: λ = h/p = hc/E
E = 25 kV
h = 4.14 × 10−15 eV second
c = 3 × 108 m/s
hc = 1.24 × 10−6 eVm
→ λ = 1.24 × 10−6/25 × 103 = ½ × 10−10 m = 0.5 Å
Answer: B
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